http://www.cnblogs.com/archy_yu/archive/2013/04/19/3018479.html
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最近在维护一个java工程,在群里面也就聊起来java的优劣!无奈一些Java的终极粉丝,总是号称性能已经不必C++差,并且很多标准类库都是大师级的人写的,如何如何稳定等等。索性就认真研究一番,他们给我的一项说明就是,在线程之间投递消息,用java已经封装好的BlockingQueue,就足够用了。
既然足够用那就写代码测试喽,简简单单写一个小程序做了一番测试:
//默认包 import java.util.concurrent.*; import base.MyRunnable; public class Test { public static void main(String[] args) { BlockingQueue<Integer> queue = new LinkedBlockingQueue<Integer>(); java.lang.Runnable r = new MyRunnable(queue); Thread t = new Thread(r); t.start(); while ( true ) { try { while ( true ) { for ( int i = 0 ;i < 10000 ;i++) { queue.offer(i); } } } catch ( Exception e) { e.printStackTrace(); } } } } //需要添加的包 package base; import java.lang.Runnable; import java.util.concurrent.*; import java.util.*; public class MyRunnable implements Runnable { public MyRunnable(BlockingQueue<Integer> queue) { this .queue = queue; } public void run() { Date d = new Date(); long starttime = d.getTime(); System.err.println(starttime); int count = 0 ; while ( true ) { try { Integer i = this .queue.poll(); if (i != null ) { count ++; } if (count == 100000 ) { Date e = new Date(); long endtime = e.getTime(); System.err.println(count); System.err.println(endtime); System.err.print(endtime - starttime); break ; } } catch (Exception e) { } } } private BlockingQueue<Integer> queue; } |
传递十万条数据,在我的测试机上面,大概需要50ms左右,倒是还可以!索性就看了一下BlockingQueue的底层实现
我在上面的测试代码中使用的offer 和 poll,就看看这两个实现函数吧,首先是offer
public E poll() { final AtomicInteger count = this .count; if (count.get() == 0 ) return null ; E x = null ; int c = - 1 ; final ReentrantLock takeLock = this .takeLock; takeLock.lock(); try { if (count.get() > 0 ) { x = extract(); c = count.getAndDecrement(); if (c > 1 ) notEmpty.signal(); } } finally { takeLock.unlock(); } if (c == capacity) signalNotFull(); return x; } |
和一般的同步线程类似,只是多加了一个signal,在学习unix环境高级编程时候,看到条件变量用于线程之间的同步,可以实现线程以竞争的方式实现同步!
poll函数的实现也是类似!
public boolean offer(E e) { if (e == null ) throw new NullPointerException(); final AtomicInteger count = this .count; if (count.get() == capacity) return false ; int c = - 1 ; final ReentrantLock putLock = this .putLock; putLock.lock(); try { if (count.get() < capacity) { insert(e); c = count.getAndIncrement(); if (c + 1 < capacity) notFull.signal(); } } finally { putLock.unlock(); } if (c == 0 ) signalNotEmpty(); return c >= 0 ; } |